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6u^2+38u-28=0
a = 6; b = 38; c = -28;
Δ = b2-4ac
Δ = 382-4·6·(-28)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-46}{2*6}=\frac{-84}{12} =-7 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+46}{2*6}=\frac{8}{12} =2/3 $
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